60t^2+120t-60=0

Solution for 60t^2+120t-60=0 equation:

60t^2+120t-60=0

a = 60; b = 120; c = -60;
Δ = b2-4ac
Δ = 1202-4·60·(-60)
Δ = 28800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{28800}=\sqrt{14400*2}=\sqrt{14400}*\sqrt{2}=120\sqrt{2}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-120\sqrt{2}}{2*60}=\frac{-120-120\sqrt{2}}{120}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+120\sqrt{2}}{2*60}=\frac{-120+120\sqrt{2}}{120}
$